Student Marks
A 12
B 60
C 80
D 71
E 30
F 45
percentile of C = 5/5 *100 = 100 (out of 5 students, 5 are having marks less then him)
percentile of B = 3/5*100 = 60% (out of 5, 3 have markses less then him)
percentile of A = 0/5*100 = 0%.
Answer:
#include
#include
void main()
{
clrscr();
int a[10],n,i,j;
int percent;
int count;
cout<<"
enter the size of array";
cin>>n;
cout<<"
enter the values";
for(i=0;i<=n-1;i++)
{
cout<<" a["< cin>>a[i];
}
for( i=0;i<=n-1;i++)
{ count=0;
for(j=0;j<=n-1;j++)
{ if(a[i]>a[j])
{
count=count+1;
}
}
percent=(count*100)/(n-1);
cout<<"
the percentile of"<<"a["< }
getch();
}
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