Student Marks

A 12

B 60

C 80

D 71

E 30

F 45

percentile of C = 5/5 *100 = 100 (out of 5 students, 5 are having marks less then him)

percentile of B = 3/5*100 = 60% (out of 5, 3 have markses less then him)

percentile of A = 0/5*100 = 0%.

Answer:

#include

#include

void main()

{

clrscr();

int a[10],n,i,j;

int percent;

int count;

cout<<"

enter the size of array";

cin>>n;

cout<<"

enter the values";

for(i=0;i<=n-1;i++)

{

cout<<" a["<

*cin>>a[i];*

}

for( i=0;i<=n-1;i++)

{ count=0;

for(j=0;j<=n-1;j++)

{ if(a[i]>a[j])

{

count=count+1;

}

}

percent=(count*100)/(n-1);

cout<<"

the percentile of"<<"a["<

}

for( i=0;i<=n-1;i++)

{ count=0;

for(j=0;j<=n-1;j++)

{ if(a[i]>a[j])

{

count=count+1;

}

}

percent=(count*100)/(n-1);

cout<<"

the percentile of"<<"a["<

*}*

getch();

}getch();

}